How do you multiply #(a+2) (a^2- 3a+7)#?

1 Answer
Jul 27, 2015

Answer:

#=color(blue)(a^3 -a^2 +a+14#

Explanation:

#color(blue)((a+2))(a^2−3a+7)#

Here, we need to multiply each term within first bracket with the three terms of the second bracket.

#=color(blue)((a))(a^2−3a+7))+ color(blue)((2))(a^2−3a+7)#

#=a^3 -3a^2 +7a+ 2a^2 -6a+14#

grouping like terms

#=a^3 +( 2a^2-3a^2) +(7a-6a)+14#
#=color(blue)(a^3 -a^2 +a+14#