# How do you multiply (c^2t^2+1)^2?

Jul 3, 2015

You can rewrite the expression as multiplication between two binomials, and use the FOIL method to multiply.

#### Explanation:

${\left({c}^{2} {t}^{2} + 1\right)}^{2} = \left({c}^{2} {t}^{2} + 1\right) \left({c}^{2} {t}^{2} + 1\right)$

The FOIL method of multiplying indicates the order in which you multiply the terms in the binomials.

$\left({c}^{2} {t}^{2} + 1\right) \left({c}^{2} {t}^{2} + 1\right)$ =

${c}^{2} {t}^{2} \cdot {c}^{2} {t}^{2} + {c}^{2} {t}^{2} \cdot 1 + 1 \cdot {c}^{2} {t}^{2} + 1 \cdot 1 {c}^{4} {t}^{4} + 2 {c}^{2} {t}^{2} + 1$ =

${c}^{4} {t}^{4} + 2 {c}^{2} {t}^{2} + 1$