How do you multiply #(m+8)(m-8)#?

2 Answers
Jan 28, 2017

Answer:

#(m+8)(m-8)=m^2-64# See explanation.

Explanation:

If you multiply this you get:

#(m+8)(m-8)= m^2cancel(+8m)cancel(-8m)-64 =m^2-64#

Jan 28, 2017

Answer:

#m^2-64#

Explanation:

#(m+8)(m-8)#
#=m(m-8)+8(m-8)#
#=m^2-8m+8m-64#=>simplify:
#=m^2-64#
Alternatively the difference 2 squares formula can be used:
#a^2-b^2=(a+b)(a-b)#
hence:
#(m+8)(m-8)=m^2-64#