How do you multiply #(x + 1)(x - 1)^2#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer Ridinion K. Jun 23, 2018 #(x+1)(x-1)^2=x^3-x^2-x+1# Explanation: Let's focus on #(x-1)^2# first. This is equivalent to #(x-1)(x-1)#. So, #(x-1)(x-1)=x^2-x-x+1# #(x-1)(x-1)=x^2-2x+1# Now multiply this result by #(x+1)# and expand: #(x+1)(x^2-2x+1)# #(x+1)(x^2-2x+1)=x^3-2x^2+x+x^2-2x+1# #(x+1)(x^2-2x+1)=x^3-x^2-x+1# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 4369 views around the world You can reuse this answer Creative Commons License