How do you multiply #(x+1)(x+4)#?

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Answer 1 · 2016-04-18T19:28:13

#x^2+5x+4#

first multiply #x# with #(x+4)# and then #1# with again #(x+4)#
so #x^2+4x+x+4#
#x^2+5x+4#

Answer 2 · 2016-04-18T19:34:43

Use FOIL to help find:

#(x+1)(x+4) = x^2+5x+4#

If you find it helpful, you can use the FOIL mnemonic to help you identify which terms to combine.

#(x+1)(x+4) = overbrace((x*x))^"First" + overbrace((x*4))^"Outside"+overbrace((1*x))^"Inside"+overbrace((1*4))^"Last"#

#=x^2+4x+x+4 = x^2+5x+4#