How do you multiply #(x+19)(x-19)#?

1 Answer
Jun 28, 2016

Answer:

#x^2# - 361

Explanation:

Start with the first set of brackets.
So #x# times the the other #x# = #x^2#
Then that same #x# (from the first set) times -19 = -19#x#
Then 19 times the #x# (from the second set) = 19#x#
Then that 19 times -19 = -361

Add it all up equals to #x^2# + 19#x# - 19#x# -361
or in other words... #x^2# - 361.