# How do you multiply (x^2-1)^3?

${\left({x}^{2} - 1\right)}^{3} = {x}^{6} - 3 {x}^{4} + 3 {x}^{2} - 1$
${\left(a - b\right)}^{3} = {a}^{3} - 3 {a}^{2} b + 3 a {b}^{2} - {b}^{3}$
${\left({x}^{2} - 1\right)}^{3} = {\left({x}^{2}\right)}^{3} - 3 {\left({x}^{2}\right)}^{2} + 3 {x}^{2} - 1 = {x}^{6} - 3 {x}^{4} + 3 {x}^{2} - 1$