# How do you multiply (x-2)(3x^2-5x+4)?

Jun 13, 2018

$3 {x}^{3} - 11 {x}^{2} + 14 x - 8$

#### Explanation:

You take the numbers in the first bracket, in this case, $x$ and $- 2$, and multiply both of those numbers with every single number in the other bracket.

$3 {x}^{3} - 5 {x}^{2} + 4 x - 6 {x}^{2} + 10 x - 8$

Jun 13, 2018

color(green)(3x^3-11x^2+14x-8

#### Explanation:

$\left(x - 2\right) \left(3 {x}^{2} - 5 x + 4\right)$

$\textcolor{w h i t e}{a a a a a a a a a a a a a}$$3 {x}^{2} - 5 x + 4$
$\textcolor{w h i t e}{a a a a a a a a a a a}$$\times \underline{x - 2}$
$\textcolor{w h i t e}{a a a a a a a a a a a a a}$$3 {x}^{3} - 5 {x}^{2} + 4 x$
$\textcolor{w h i t e}{a a a a a a a a a a a a a a a a}$$- 6 {x}^{2} + 10 x - 8$
$\textcolor{w h i t e}{a a a a a a a a a a a a a}$$\overline{3 {x}^{3} - 11 {x}^{2} + 14 x - 8}$

$\textcolor{w h i t e}{a a a a a a a a a a a a a}$color(green)(3x^3-11x^2+14x-8