How do you multiply #(x-2)(3x^2-5x+4)#?

2 Answers
Jun 13, 2018

Answer:

#3x^3-11x^2+14x-8#

Explanation:

You take the numbers in the first bracket, in this case, #x# and #-2#, and multiply both of those numbers with every single number in the other bracket.

#3x^3-5x^2+4x-6x^2+10x-8#

Jun 13, 2018

Answer:

#color(green)(3x^3-11x^2+14x-8#

Explanation:

#(x-2)(3x^2-5x+4)#

#color(white)(aaaaaaaaaaaaa)##3x^2-5x+4#
#color(white)(aaaaaaaaaaa)## xx underline(x-2)#
#color(white)(aaaaaaaaaaaaa)##3x^3-5x^2+4x#
#color(white)(aaaaaaaaaaaaaaaa)##-6x^2+10x-8#
#color(white)(aaaaaaaaaaaaa)##overline(3x^3-11x^2+14x-8)#

#color(white)(aaaaaaaaaaaaa)##color(green)(3x^3-11x^2+14x-8#