How do you multiply #(x^2+3x-5) (x^3+4x^2-3x+2) #?

1 Answer
Aug 23, 2015

Answer:

#=color(blue)(x^5+7x^4+4x^3-27x^2+21x-10#

Explanation:

#color(blue)((x^2+3x−5))(x^3+4x^2−3x+2)#

#=color(blue)((x^2))(x^3+4x^2−3x+2) +color(blue)((3x))(x^3+4x^2−3x+2) + color(blue)((-5))(x^3+4x^2−3x+2)#

#=x^5+4x^4-3x^3+2x^2+color(blue)(3x^4+12x^3-9x^2+6x) -5x^3-20x^2+15x-10#

Adding like terms
#=color(blue)(x^5+7x^4+4x^3-27x^2+21x-10#