# How do you multiply (x+3)(x-2)(6x-5)?

Oct 27, 2016

#### Answer:

$6 {x}^{3} + {x}^{2} - 41 x + 30$

#### Explanation:

Start by multiplying the first two then multiply the one you find by the third

$\left(x + 3\right) \left(x - 2\right) \left(6 x - 5\right) = \left({x}^{2} + x - 6\right) \left(6 x - 5\right) = 6 {x}^{3} - 5 {x}^{2} + 6 {x}^{2} - 5 x - 36 x + 30 = 6 {x}^{3} + {x}^{2} - 41 x + 30$

Hope this helps :)