Question

How do you multiply `(x^ { - 3} y ^ { - 1} ) ^ { - 1} ( x ^ { - 3} y ^ { 0} ) ^ { 2}`?

Answer 1

The Answer is `x^-3y`.

Explanation:

This can be divided into 2 parts :
1. `(x^-3y^-1)^-1` = `x^3y`
2. `(x^-3y^0)^2` = `x^-6y^0` = `x^-6` because `y^0` = 1.

therefore the answer becomes `(x^3y)(x^-6)` = `x^-3y`