How do you multiply #(x+4)(3x^2-8x-7)#?

1 Answer
Mar 18, 2018

Answer:

#3x^3 +4x^2-39x-28#

Explanation:

To multiply two polynomials requires distribution. Each term of one polynomial must multiple each of the terms in the other polynomial.

We start with:

#(x+4)(3x^2-8x-7)#

#=x(3x^2-8x-7) + 4(3x^2-8x-7)#

First we multiply #x# from the first polynomial by each term of the second polynomial:

#=3x^3 -8x^2-7x + 4(3x^2-8x-7)#

Now we multiply #4# from the first polynomial by each term of the second polynomial:

#=3x^3 - 8x^2 -7x + 12x^2 -32x-28#

Now we simplify:

#=color(blue)(3x^3) - color(orange)(8x^2) -color(red)(7x) + color(orange)(12x^2) -color(red)(32x)-28#

#=color(blue)(3x^3) +color(orange)(4x^2)-color(red)(39x)-28#

#=> color(green)(3x^3 +4x^2-39x-28)#