# How do you multiply (x+5)(2x^2+x-10)?

Jun 25, 2015

 = color(blue)(2x^3 + 11x^2 - 5x -50

#### Explanation:

$\textcolor{b l u e}{\left(x + 5\right)} \left(2 {x}^{2} + x - 10\right)$

• Here, we first multiply $\textcolor{b l u e}{x}$contained in the first bracket with all three terms of second bracket:

$= \textcolor{b l u e}{x} . \left(2 {x}^{2}\right) + \textcolor{b l u e}{x} . x + \textcolor{b l u e}{x} . \left(- 10\right)$

$= 2 {x}^{3} + {x}^{2} - 10 x$........................$\left(1\right)$

• Now, we multiply $\textcolor{b l u e}{5}$ contained in the first bracket with all three terms of second bracket:

$= \textcolor{b l u e}{5} . \left(2 {x}^{2}\right) + \textcolor{b l u e}{5} . x + \textcolor{b l u e}{5} . \left(- 10\right)$

$= 10 {x}^{2} + 5 x - 50$.........................$\left(2\right)$

combining $\left(1\right)$ and $\left(2\right)$

 = color(blue)(2x^3 + 11x^2 - 5x -50