# How do you mutiply (2p + 7)(3p - 9)?

Jun 24, 2015

$\left(\textcolor{red}{2 p} + \textcolor{b l u e}{7}\right) \left(3 p - 9\right) = \left(\textcolor{red}{2 p}\right) \left(3 p - 9\right) + \left(\textcolor{b l u e}{7}\right) \left(3 p - 9\right)$
$= \textcolor{red}{6 {p}^{2} - 18 p} + \textcolor{b l u e}{21 p - 63}$
$= 6 {p}^{2} + 3 p - 63$

#### Explanation:

There are several ways of doing this multiplication.

The method demonstrated in the answer (above) uses the distributive property.

Because we are dealing with the multiplication of two binomials you could use FOIL. (ask if you want to see this method).

Tabular multiplication could also be used. (again, ask if you want to see this method).