How do you name the curve given by the conic #r=6#?

1 Answer
Dec 9, 2016

Answer:

It is a circle with center at #(0,0)# and radius #6#.

Explanation:

#r=6# denotes locus of a point which moves so that it's distance from origin is always constant and at #6#.

It is quite apparent that this is the equation of a circle with center at origin and radius#6#.

Further, relation between polar coordinates #(r,theta)# and Cartesian coordinates #(x,y)# is given by #x=rcostheta# and #x=rsintheta# i.e. #r^2=x^2+y^2#.

Hence, #r=6# on squaring translates into #x^2+y^2=36# and is equation of circle with center at #(0,0)# and radius is #6#.