How do you normalize # (18i -30j -12k) #?

1 Answer
May 26, 2016

Answer:

Normalising a vector involves dividing each of its elements by its length, to yield a new vector of length 1 unit in the same direction as the original vector. In this case, the length of the vector is #37# units so the normalised vector is #(18/37i-30/37j-12/37k)#.

Explanation:

Length of the vector:

#l=sqrt(18^2+(-30)^2+(-12)^2)=sqrt(324+900+144)=sqrt(1368)~~37#