How do you normalize # (3i – 4j + 4k) #?

1 Answer
Jul 1, 2017

Answer:

The answer is #=3/sqrt41i-4/sqrt41j+4/sqrt41k#

Explanation:

Let #vecv=<3,-4,4>#

The magnitude of #vecv# is

#||vecv||=||<3,-4,4>||=sqrt(3^2+(-4)^2+4^2)=sqrt(9+16+16)=sqrt41#

Therefore, the normalized vector is

#hatv=vecv/(||vecv||)=1/sqrt41*<3,-4,4>#