# How do you normalize ( i - 2 j + 3 k )?

A vector is normalised by dividing that with its magnitude. Suppose if $\setminus \vec{{A}_{}} = {A}_{x} \setminus \hat{i} + {A}_{y} \setminus \hat{j} + {A}_{z} \setminus \hat{k}$ is the vector, its magnitude $A = | \setminus \vec{{A}_{}} | = \setminus \sqrt{{A}_{x}^{2} + {A}_{y}^{2} + {A}_{z}^{2}}$.
So the normalised vector is $\setminus \hat{A} = \setminus \frac{\vec{{A}_{}}}{A} = {A}_{x} / A \setminus \hat{i} + {A}_{y} / A \setminus \hat{j} + {A}_{z} / A \setminus \hat{k}$.