How do you perform the operation and write the result in standard form given #sqrt(-10)^2#? Precalculus Complex Numbers in Trigonometric Form Multiplication of Complex Numbers 1 Answer Kalyanam S. Jul 11, 2018 #color(cyan)(=> 10 i)# Explanation: #sqrt(-10^2)# #=> sqrt(i^2 * 10^2)# as #i^2 -= -1# #=> sqrt (i^2) * sqrt(10^2)# #=> 10 i# Answer link Related questions How do I multiply complex numbers? How do I multiply complex numbers in polar form? What is the formula for multiplying complex numbers in trigonometric form? How do I use the modulus and argument to square #(1+i)#? What is the geometric interpretation of multiplying two complex numbers? What is the product of #3+2i# and #1+7i#? How do I use DeMoivre's theorem to solve #z^3-1=0#? How do I find the product of two imaginary numbers? How do you simplify #(2+4i)(2-4i)#? How do you multiply #(-2-8i)(6+7i)#? See all questions in Multiplication of Complex Numbers Impact of this question 1468 views around the world You can reuse this answer Creative Commons License