How do you plot the following graph: #y=-abs(x+4)#?

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Answer 1 · 2016-12-03T14:26:47

Graph is inserted. The second graph is for #y=+-|x+4|# The third is for #y=|x+4|#

#y<=0# and the x-intercept ( y = 0 ) is #-4#.

The given equation is the combined ( half line ) equations

#y = -(x+4), x>=-4# and

#y= -(-(x+4)), x<=-4#.

The inserted graphs are respectively for

#y=-|x+4|, y=+-|x+4| and y=|x+4|#
.

graph{y+|x+4|=0 [-10, 10, -5, 5]}

graph{y^2-(x+4)^2=0 [-10, 10, -5, 5]}

graph{y-|x+4|=0 [-10, 10, -5, 5]}