# How do you plot the following graph: y=-abs(x+4)?

Dec 3, 2016

Graph is inserted. The second graph is for $y = \pm | x + 4 |$ The third is for $y = | x + 4 |$

#### Explanation:

$y \le 0$ and the x-intercept ( y = 0 ) is $- 4$.

The given equation is the combined ( half line ) equations

$y = - \left(x + 4\right) , x \ge - 4$ and

$y = - \left(- \left(x + 4\right)\right) , x \le - 4$.

The inserted graphs are respectively for

$y = - | x + 4 | , y = \pm | x + 4 | \mathmr{and} y = | x + 4 |$
.

graph{y+|x+4|=0 [-10, 10, -5, 5]}

graph{y^2-(x+4)^2=0 [-10, 10, -5, 5]}

graph{y-|x+4|=0 [-10, 10, -5, 5]}