How do you prove #cos ((2pi)/3)#?

1 Answer
Mar 21, 2016

Let's convert to degrees, which are usually easier to work with.

Explanation:

Use the conversion rate #180/pi# to convert to degrees.

#=> (2pi)/3 xx 180/pi#

#= 120 degrees.

We must now determine the reference angle for 120 degrees. Since 120 degrees is in quadrant II, the reference angle is found by using the expression #180 - theta#, where #theta# is the angle in degrees.

Calculating we get a reference angle of 60 degrees. We must now apply our knowledge of the special triangles to continue.

The special triangle that contains 60 degrees is the 30-60-90 degrees, that has side lengths of #1, sqrt(3) and 2#, respectively. So, the hypotenuse measures 2, the side opposite our angle measures #sqrt(3)# and the side adjacent measures #1#.

Applying the definition that cos = adjacent/hypotenuse, we find that our ratio is #1/2#. However, since we're in quadrant II the x axis is negative and therefore our ratio is in fact #-1/2#.

Thus, #cos((2pi)/3) = -1/2#

You can use the acronym #C-A-S-T (Q. 4-3-2-1)# to remember in which quadrants the ratios are positive. For example, we can say with this acronym that cos is positive in quadrant #IV#.

Feel free to ask anything more either on my Socratic dashboard or on the main questions page. I understand that this might at first seem like a long and complicated process.

Practice exercises

  1. Find the exact value of each expression.

#a) tan300#

#b) sin((7pi)/6)#

Good luck!