How do you prove #Cos(x-(3pi)/2)=-sinx#?

Question

10469 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-12T01:58:33

Using the identities

We have:

#cos(x-(3pi)/2) = cos((x-pi)-pi/2)#

#=sin(x-pi)#

#=sin((x-pi/2)-pi/2)#

#=-cos(x-pi/2)#

#=-sin(x)#