How do you prove: #cotx-cosx=cotx(1-sinx)#?

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Answer 1 · 2015-04-16T09:43:56

Right Hand Side :

#cotx(1-sinx)#

# = cot x - cotx*sinx# (Distributive Property of Multiplication)

We know that #color(blue)(cot x = cos x / sin x#

# = cot x - (cos x/cancel sin x)*cancel sinx#

# = cot x - cos x# is the same as the Left hand Side

Hence proved.