# How do you simplify (-1+2i)(11-i) and write the complex number in standard form?

##### 1 Answer
Aug 8, 2017

$- 9 + 23 i$

#### Explanation:

$\text{expand the factors using FOIL}$

$= - 11 + i + 22 i - 2 {i}^{2}$

$\left[{i}^{2} = {\left(\sqrt{- 1}\right)}^{2} = - 1\right]$

$= - 11 + 23 i + 2$

$= - 9 + 23 i \leftarrow \textcolor{red}{\text{ in standard form}}$