How do you simplify #(-1+2i)(11-i)# and write the complex number in standard form?
1 Answer
Aug 8, 2017
Explanation:
#"expand the factors using FOIL"#
#=-11+i+22i-2i^2#
#[i^2=(sqrt(-1))^2=-1]#
#=-11+23i+2#
#=-9+23ilarrcolor(red)" in standard form"#
