How do you simplify #(1-8i)(-2-2i)(-5+7i)#?
1 Answer
Jul 29, 2016
Explanation:
#(1-8i)(-2-2i)#
#=(1)(-2)+(-8i)(-2)+(1)(-2i)+(-8i)(-2i)#
#=-2+16i-2i+16i^2#
#=-18+14i#
#(-18+14i)(-5+7i)#
#=(-18)(-5)+(14i)(-5)+(-18)(7i)+(14i)(7i)#
#=90-70i-126i+98i^2#
#=-8-196i#
