How do you simplify #1/i^3#?

1 Answer
Sep 18, 2016

#i#

Explanation:

The first step is to evaluate #i^3#

#color(orange)"Reminder " color(red)(bar(ul(|color(white)(a/a)color(black)(i^2=(sqrt(-1))^2=-1)color(white)(a/a)|)))#

#rArri^3=i^2.i=-i#

Thus #1/i^3=1/(-i)#

multiply numerator/denominator by i.

#rArr1/(-i)xxi/i=i/(-i^2)=i#