How do you simplify #(1+i)(3+2i)#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer Tony B Jul 6, 2016 #1+5i# Explanation: #color(blue)((1+i))color(brown)((3+2i))# #color(brown)(color(blue)(1)(3+2i)" "color(blue)(+i)(3+2i))# #3+2i" "+" "3i+2i^2# But #i^2=-1 =>2i^2=-2# #3+5i-2" "=" "1+5i# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 2298 views around the world You can reuse this answer Creative Commons License