How do you simplify #(10 - 4 * 13+ 19) div 23# using order of operations? Algebra Expressions, Equations, and Functions PEMDAS 1 Answer Shwetank Mauria Apr 25, 2016 #(10-4*13+19)-:23=-1# Explanation: #(10-4*13+19)-:23# = #(10-52+19)-:23# = #(29-52)-:23# = #(-23)-:23=-1# Answer link Related questions What is PEMDAS? How do you use PEMDAS? How do you use order of operations to simplify #3(7-2)-8#? What are common mistakes students make with PEMDAS? How do you evaluate the expression #5[8+(3-1)]-2#? How do you simplify the expression #4(30-(3+1)^2)#? How do you evaluate the expression #x^4+x# if x=2? Is it okay to add first before subtracting in #4-6+3#? How do you simplify #(-3)^2+12*5#? How do you simplify #(4-2)^3-4*8+21div3#? See all questions in PEMDAS Impact of this question 1242 views around the world You can reuse this answer Creative Commons License