# How do you simplify -10/5times2+8times(6-4)-3times4 using PEMDAS?

Jul 24, 2016

$- \frac{10}{5} \times 2 + 8 \times \left(6 - 4\right) - 3 \times 4 = 0$

#### Explanation:

PEMDAS stands for Parentheses, Exponents, Multiplication and Division, and Addition and Subtraction. Hence we solve in this order - first parentheses, then exponents, then multiplication and division and finally addition and subtraction.

Hence $- \frac{10}{5} \times 2 + 8 \times \left(6 - 4\right) - 3 \times 4$

= $- \frac{10}{5} \times 2 + 8 \times 2 - 3 \times 4$

= $- \frac{20}{5} + 16 - 12$

= $- 4 + 16 - 12$

= $0$

Jul 26, 2016

$= 0$

#### Explanation:

When working with calculations involving different operations, the first thing to do is to to count the number of terms. Terms are separated by + and - signs.

There must be a final answer fro each term before we can add or subtract them from left to right.

$\textcolor{m a \ge n t a}{- \frac{10}{5} \times 2} \textcolor{b l u e}{+ 8 \times \left(6 - 4\right)} \textcolor{\mathmr{and} a n \ge}{- 3 \times 4}$ has three terms.

In each term do the strongest operations first (brackets first and , powers before multiply or divide)

$\textcolor{m a \ge n t a}{- 2 \times 2} \textcolor{b l u e}{+ 8 \times \left(2\right)} \textcolor{\mathmr{and} a n \ge}{- 12}$

$\textcolor{m a \ge n t a}{- 4} \textcolor{b l u e}{+ 16} \textcolor{\mathmr{and} a n \ge}{- 12}$

Now work from left to right, or re-arrange the terms making sure that the signs stay with the correct term.

=$\textcolor{b l u e}{+ 16} \textcolor{m a \ge n t a}{- 4} \textcolor{\mathmr{and} a n \ge}{- 12}$

=$0$