How do you simplify #(10i)*-7+(4i)#? Precalculus Complex Numbers in Trigonometric Form Multiplication of Complex Numbers 1 Answer Kalyanam S. Jul 11, 2018 Case -1 # 10i * (-7 + 4i) = -40 - 70i# Case 2 # (10i * -7) + 4i = - 66 i # Explanation: Case 1 : #10 i * (-7 + 4i)# #=> (10i * -7 ) + (10 i * 4 i)#, removing bracket and regrouping #=> -70 i + 40 i^2#, multiplying #=> -40 - 70 i#, simplifying, as #i^2 = -1# Case 2 : #(10i * -7) + 4i# #=> -70i + 4i# #=> - 66i# Answer link Related questions How do I multiply complex numbers? How do I multiply complex numbers in polar form? What is the formula for multiplying complex numbers in trigonometric form? How do I use the modulus and argument to square #(1+i)#? What is the geometric interpretation of multiplying two complex numbers? What is the product of #3+2i# and #1+7i#? How do I use DeMoivre's theorem to solve #z^3-1=0#? How do I find the product of two imaginary numbers? How do you simplify #(2+4i)(2-4i)#? How do you multiply #(-2-8i)(6+7i)#? See all questions in Multiplication of Complex Numbers Impact of this question 1529 views around the world You can reuse this answer Creative Commons License