How do you simplify $11^(1/2) * 11^(7/3) *11^(1/6)$ ?

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Answer 1 · 2015-05-27T01:50:25

In general $b^p*b^q+b^r = b^(p+q+r)$

So
$11^(1/2)*11^(7/3)*11^(1/6)$

$= 11 ^(1/2+7/3+1/6)$

$= 11 ^((3+14+1)/6)$

$= 11^3$

$= 1331$

How do you simplify 11^(1/2) * 11^(7/3) *11^(1/6)11^(1/2) * 11^(7/3) *11^(1/6)?