How do you simplify #(-11-2i)(-7+12i)#? Precalculus Complex Numbers in Trigonometric Form Multiplication of Complex Numbers 1 Answer Ratnaker Mehta Jul 22, 2017 #" The Exp.="101-118i.# Explanation: #"The Expression="(-11-2i)(-7+12i),# #=-11(-7+12i)-2i(-7+12i),# #=77-132i+14i-24i^2,# #=77-118i-24(-1),...........[because, i^2=-1]# #=77+24-118i,# # rArr" The Exp.="101-118i.# Answer link Related questions How do I multiply complex numbers? How do I multiply complex numbers in polar form? What is the formula for multiplying complex numbers in trigonometric form? How do I use the modulus and argument to square #(1+i)#? What is the geometric interpretation of multiplying two complex numbers? What is the product of #3+2i# and #1+7i#? How do I use DeMoivre's theorem to solve #z^3-1=0#? How do I find the product of two imaginary numbers? How do you simplify #(2+4i)(2-4i)#? How do you multiply #(-2-8i)(6+7i)#? See all questions in Multiplication of Complex Numbers Impact of this question 1363 views around the world You can reuse this answer Creative Commons License