# How do you simplify 12-15 sqrt 6+8 sqrt 6-10 sqrt 36?

Jan 28, 2016

When adding/subtracting radicals, the numbers under the radical sign ($\sqrt{,} \sqrt[3]{,} \sqrt[4]{,} e t c$), must be equal.

#### Explanation:

12 - 15$\sqrt{6}$ + 8#sqrt(6) - 10(6)

We can now combine the constant terms (12 and 60) and the $\sqrt{6}$ terms.

12 - 60 + (-15 + 8)$\sqrt{6}$

-48 - 7$\sqrt{6}$

The answer is -48 - 7$\sqrt{6}$