How do you simplify $12^{2} - [20 \div 2 + 5 (6 + 1)]$ $12^2-[20div2+5(6+1)]$ ?

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Answer 1 · 2016-11-14T09:55:33

$99$ $99$

Identify the different terms first.
Each term will simplify to a single answer and these will be added or subtracted only in the last line.

Within each term, the order of operations is:

-Brackets,
-powers and roots,
-multiply and divide

There are 2 terms. but inside the bracket there are also 2 terms.

$12^{2} - [20 \div 2 + 5 (6 + 1)]$ $color(blue)(12^2) -[color(red)(20div2)color(purple)(+5(6+1))]$

$= 144 - [10 + 5 (7)]$ $=color(blue)(144) -[color(red)(10)color(purple)(+5(7))]$

$= 144 - [10 + 35]$ $=color(blue)(144) -[color(red)(10)color(purple)(+35)]$

$= 144 - 45$ $=color(blue)(144) -45$

$= 99$ $=99$

How do you simplify 12^2-[20div2+5(6+1)]122−[20÷2+5(6+1)]12^2-[20div2+5(6+1)]?