Question

How do you simplify `(12xy^4)/(8x^2y^3)`?

Answer 1

`(3y)/(2x)` with `(x!=0, y!=0)`

Explanation:

`(12xy^4)/(8x^2y^3)` Note : `(x!=0, y!=0)`

Decompose the expression :

`(12xy^4)/(8x^2y^3) = (2*2*3*x*y*y*y*y)/(2*2*2*x*x*y*y*y)`

And cancels pairs :

`(color(green)(cancel(2)*cancel(2)*3)*color(blue)(cancel(x))*color(red)(cancel(y)*cancel(y)*cancel(y)*y))/(color(green)(cancel(2)*cancel(2)*2)*color(blue)(cancel(x)*x)*color(red)(cancel(y)*cancel(y)*cancel(y))) = (3y)/(2x)`

Then : `(12xy^4)/(8x^2y^3) = (3y)/(2x)` with `(x!=0, y!=0)`