How do you simplify #14sqrt75#?

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Answer 1 · 2018-03-09T14:22:35

See below

Given expression,

#14 sqrt(75)#

We get,

#=14 * sqrt(75) = 14 * sqrt(25*3) = 14 * sqrt (5^2*3) = #

#=14* cancel sqrt(5^cancel(2))*sqrt(3)# (You cancel the #sqrt# and #5^color(red)2)#

#=14*5sqrt(3)=#

#= 70 sqrt(3)#

Answer 2 · 2018-03-09T15:24:47

#70sqrt3#

#14sqrt75#

#:.=14xxsqrt(3*5*5)#

#:.sqrt5xxsqrt5=5#

#:.=14*5sqrt3#

#:.=70sqrt3#