How do you simplify #(16xy^7)/(4xy^3)#?

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Answer 1 · 2018-06-14T05:55:46

#4y^4#

Exponential Laws:

#1/a = a^-1#

#1/a^2 = a^-2#

#a/a^2 = a^(1-2) = a^-1#

So now lets simplify:

#(16xy^7)/(4xy^3)# = #(16cancel(x)y^(7-3))/(4cancel(x))# -----> simplifying variables first.

#(16cancel(x)y^(7-3))/(4cancel(x))# = #(16y^4)/4# = #4y^4#

Hope this helps!