# How do you simplify (16xy^7)/(4xy^3)?

Jun 14, 2018

$4 {y}^{4}$

#### Explanation:

Exponential Laws:

$\frac{1}{a} = {a}^{-} 1$

$\frac{1}{a} ^ 2 = {a}^{-} 2$

$\frac{a}{a} ^ 2 = {a}^{1 - 2} = {a}^{-} 1$

So now lets simplify:

$\frac{16 x {y}^{7}}{4 x {y}^{3}}$ = $\frac{16 \cancel{x} {y}^{7 - 3}}{4 \cancel{x}}$ -----> simplifying variables first.

$\frac{16 \cancel{x} {y}^{7 - 3}}{4 \cancel{x}}$ = $\frac{16 {y}^{4}}{4}$ = $4 {y}^{4}$

Hope this helps!