# How do you simplify 2^2/(3/2)^-2?

Jun 2, 2016

${2}^{2} / \left({\left(\frac{3}{2}\right)}^{- 2}\right) = 9$
Using negative exponents ${a}^{- x} = \frac{1}{a} ^ x$ or $\frac{1}{{a}^{- x}} = {a}^{x}$.
Hence ${2}^{2} / \left({\left(\frac{3}{2}\right)}^{- 2}\right) = {2}^{2} \times {\left(\frac{3}{2}\right)}^{2}$
= ${2}^{2} \times {3}^{2} / {2}^{2} = {3}^{2} = 9$