# How do you simplify (2/3)^4/((2/3)^-5(2/3)^0)?

${\left(\frac{2}{3}\right)}^{9}$
${\left(\frac{2}{3}\right)}^{4} / {\left(\frac{2}{3}\right)}^{-} 5$ would equal $\left(\frac{2}{3}\right)$ to the ninth power, since $4 - \left(- 5\right) = 9$, thus ${\left(\frac{2}{3}\right)}^{4} / \left({\left(\frac{2}{3}\right)}^{-} 5\right) = {\left(\frac{2}{3}\right)}^{9}$.
As for ${\left(\frac{2}{3}\right)}^{0}$, that equals 1, since ${x}^{0}$is 1, and anything times 1 is itself. Hope this helped.