How do you simplify #(2/3)^4/((2/3)^-5(2/3)^0)#?

1 Answer

Answer:

#(2/3)^9#

Explanation:

When dividing monomials, you subtract the exponents. I'll show this step below:

#(2/3)^4/(2/3)^-5# would equal #(2/3)# to the ninth power, since #4-(-5) = 9#, thus #(2/3)^4/((2/3)^-5)= (2/3)^9#.

As for #(2/3)^0 #, that equals 1, since #x^0#is 1, and anything times 1 is itself. Hope this helped.