How do you simplify #(2-3i)(-1+4i)#?

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Answer 1 · 2018-05-15T06:05:26

#(2-3i)(-1+4i)=10+11i#

Let's use the distributive property.

#(2-3i)(-1+4i)=2(-1+4i)-3i(-1+4i)#

And let's use it twice more.

#2(-1+4i)-3i(-1+4i)=-2+8i+3i-12i^2#

Now remember that #i^2=-1#.

#-2+8i+3i-12i^2=-2+8i+3i-12(-1)#

#=-2+8i+3i+12#

#=10+11i#