How do you simplify #-2/7 + (-2/5)#?

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Answer 1 · 2017-03-06T18:23:43

See the entire simplification process below:

First, we must put the fractions over a common denominator (35 in this case) by multiplying each fraction by the appropriate form of #1#:

#(5/5 xx -2/7) + (7/7 xx -2/5) ->#

#-10/35 + (-14/35)#

We can now add the numerators over a common denominator:

#(-10 + (-14))/35 ->#

#(-10 - 14)/35 ->#

#-24/35#