How do you simplify #(2-9i)(9-6i)# and write the complex number in standard form?
1 Answer
Jul 26, 2016
Explanation:
Using that
#=18-12i-81i+54i^2#
#=18-12i-81i-54#
#=-36-93i#
Using that
#=18-12i-81i+54i^2#
#=18-12i-81i-54#
#=-36-93i#