How do you simplify #(2-p)/(p^2-p-2)#?

2 Answers
Sep 3, 2016

Answer:

#-1/(p+1)#

Explanation:

Well you have to do something so factorise the denominator
#(2-p)/((p-2)(p+1))#

And it helps
#-((p-2))/((p-2)(p+1))#

Cancel
#-1/(p+1#

Sep 3, 2016

Answer:

#(-1)/(p+1)#

Explanation:

The first step is to factorise the denominator.

#rArrp^2-p-2#

Consider the factors of - 2 which sum to give the coefficient of the middle term, that is - 1.

These are - 2 and + 1 , since.

#(-2xx+1)=-2" and " -2+1=-1#

#rArrp^2-p-2=(p-2)(p+1)#

Fraction can now be expressed as #(2-p)/((p-2)(p+1))#

Take out a common factor of - 1 in the numerator.

#rArr2-p=-1(p-2)#

and now we have a fraction which may be simplified.

#rArr(-1cancel((p-2)))/(cancel((p-2))(p+1))=(-1)/(p+1)=-1/(p+1)#