# How do you simplify (27x^6y^12)^(2/3)?

Nov 1, 2015

$9 {x}^{4} {y}^{8}$

#### Explanation:

Using laws of exponents we get

${\left(27 {x}^{6} {y}^{12}\right)}^{\frac{2}{3}} = {27}^{\frac{2}{3}} {\left({x}^{6}\right)}^{\frac{2}{3}} {\left({y}^{12}\right)}^{\frac{2}{3}}$

$= \sqrt[3]{{27}^{2}} \cdot {x}^{\frac{12}{3}} \cdot {y}^{\frac{24}{3}}$

$= 9 {x}^{4} {y}^{8}$