How do you simplify #(2e-2f)(2f+8)#?

1 Answer
Oct 6, 2015

Answer:

Use the distributive property to obtain:
#color(white)("XXX")4ef+16e-4f^2-16f#
or
Extract factors:
#color(white)("XXX")4(e-f)(f+4)#
Depending upon what you view as a "simplification"

Explanation:

#(color(red)(2e)-color(blue)(2f))color(green)((2f+8))#
#color(white)("XXX")=(color(red)(2e))(color(green)(2f+8))+(color(blue)(-2f))(color(green)(2f+8))#
#color(white)("XXX")=4ef+16e-2f^2-16f#
or
Extracting factors of #2# from each of the first and second original factors to get:
#color(white)("XXX")4(e-f)(f+4)#