How do you simplify #(-2f^3g^2h^0)/(8f^2g^2)#?
2 Answers
Jun 1, 2017
ans- -1fh^0/4
Explanation:
-2 (f^3) (g^2) (h^0)/ 8f^2g^2 ----------------(on solving and cancelling in both numerator and denominator f^2, g^2 are common and hence get cancelled)
= -1f(h^0)/4 (thus answer)
...............................hope it helps.....................:)
Jun 1, 2017
#(-f)/4#
Explanation:
#(-2f^3g^2h^0)/(8f^2g^2)#
#(-2)/8xxf^(3-2)g^(2-2)xxh^0#
#(-1)/4xxfxxg^0xxh^0#
#(-f)/4#
