How do you simplify #-2i(-4i)#?
1 Answer
Jun 9, 2016
Explanation:
#-2i(-4i)=-2ixx-4i=8i^2# now
#i^2=(sqrt(-1))^2=-1#
#rArr-2i(-4i)=8i^2=8xx(-1)=-8#
#-2i(-4i)=-2ixx-4i=8i^2# now
#i^2=(sqrt(-1))^2=-1#
#rArr-2i(-4i)=8i^2=8xx(-1)=-8#