How do you simplify ((2r^3t^6)/(5u^9))^4(2r3t65u9)4? Prealgebra Exponents, Radicals and Scientific Notation Exponents 1 Answer Shwetank Mauria Aug 23, 2017 ((2r^3t^6)/(5u^9))^4=(16r^12t^24)/(625u^36)(2r3t65u9)4=16r12t24625u36 Explanation: ((2r^3t^6)/(5u^9))^4(2r3t65u9)4 = (2^4r^(3xx4)t^(6xx4))/(5^4u^(9xx4))24r3×4t6×454u9×4 = (16r^12t^24)/(625u^36)16r12t24625u36 Answer link Related questions How do you simplify c^3v^9c^-1c^0c3v9c−1c0? How do you simplify (- 1/5)^-2 + (-2)^-2(−15)−2+(−2)−2? How do you simplify (4^6)^2 (46)2? How do you simplify 3x^(2/3) y^(3/4) (2x^(5/3) y^(1/2))^3 3x23y34(2x53y12)3? How do you simplify 4^3·4^543⋅45? How do you simplify (5^-2)^-3(5−2)−3? How do you simplify and write (-5.3)^0(−5.3)0 with positive exponents? How do you factor 12j^2k - 36j^6k^6 + 12j^212j2k−36j6k6+12j2? How do you simplify the expression 2^5/(2^3 times 2^8)2523×28? When can I add exponents? See all questions in Exponents Impact of this question 2379 views around the world You can reuse this answer Creative Commons License