How do you simplify #2xsqrt(20x^20)#?

1 Answer
Apr 22, 2017

Answer:

#4x^11sqrt5#

Explanation:

#2xsqrt(20x^20)#

#sqrt(a) = a^(1/2)#

#(a^m)^n=a^(m*n)#

using these two laws:

#sqrt(x^20) = (x^20)^(1/2)#

#=x^(20/2)#

#= x^10#

#sqrt(20x^20) = sqrt(20) * x^10#

#sqrt(20) = sqrt(4)*sqrt(5) = 2sqrt5#

#sqrt(20x^20) = 2sqrt5*x^10#

#2xsqrt(20x^20) = 2*sqrt5*x^10*2x#
#=4x^11sqrt5#