How do you simplify #2xsqrt(20x^20)#?

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Answer 1 · 2017-04-22T18:46:45

#4x^11sqrt5#

#2xsqrt(20x^20)#

#sqrt(a) = a^(1/2)#

#(a^m)^n=a^(m*n)#

using these two laws:

#sqrt(x^20) = (x^20)^(1/2)#

#=x^(20/2)#

#= x^10#

#sqrt(20x^20) = sqrt(20) * x^10#

#sqrt(20) = sqrt(4)*sqrt(5) = 2sqrt5#

#sqrt(20x^20) = 2sqrt5*x^10#

#2xsqrt(20x^20) = 2*sqrt5*x^10*2x#
#=4x^11sqrt5#