# How do you simplify (2y^-9h^2)(2y^0h^-4)^-6?

$\left(\frac{1}{32}\right) \left({h}^{26} / {y}^{9}\right)$
${\left({a}^{m}\right)}^{n} = {a}^{m n} \mathmr{and} {\left(a b c\right)}^{n} = {a}^{n} {b}^{n} {c}^{n}$
The second factor is ${\left(2 X .1 . X {h}^{- 4}\right)}^{- 6} = {2}^{- 6} {1}^{- 6} {h}^{\left(- 4\right) \left(- 6\right)} = {2}^{- 6} {h}^{24}$.
${a}^{m} {a}^{n} = {a}^{m + n}$.
The given expression simplifies to ${2}^{1 - 6} {y}^{- 9} {h}^{2 + 24} = \left(\frac{1}{32}\right) \left({h}^{26} / {y}^{9}\right)$.